Biggest fish caught by Thakur, AUS Dhurandhar kept watching after being bold

New Delhi. Shardul Thakur has trapped Australia’s most dangerous batsman in his net. Yes, Thakur has shown the way to the pavilion by bowling the experienced opposition batsman Smith, who is proving to be a headache for Team India. Smith faced a total of 268 balls while batting at number four in the first innings for his team. Meanwhile, managed to score 121 runs at a strike rate of 45.14. During this, 19 excellent fours came out of his bat.

Smith became bold like this:

Steve Smith’s bat was going on fiercely in The Oval. Indian bowlers were not looking very effective against them. Meanwhile, Indian captain Rohit Sharma handed over the ball to Thakur with a hope. Lord Thakur bowled him on the very first ball of the 99th over and gave the Indian fans a chance to be happy. Smith was bowled due to the inner edge of the bat in an attempt to stop the ball going out.

WTC Final🏆. WICKET! 98.1: Steven Smith 121(268) b Shardul Thakur, Australia 387/6@BCCI #INDvsAUS #WTC2023Final pic.twitter.com/IKm45bv8Zq

— Malik of Twitter 🐦 (@sayontanroy) June 8, 2023

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Tags: india vs australia, Shardul thakur, steven smith, WTC Final